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Salesforce Updated Salesforce-MuleSoft-Developer-I Exam Questions and Answers by ronnie

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Salesforce Salesforce-MuleSoft-Developer-I Exam Overview :

Exam Name: Salesforce Certified MuleSoft Developer 1 Exam (SP24)
Exam Code: Salesforce-MuleSoft-Developer-I Dumps
Vendor: Salesforce Certification: Salesforce MuleSoft
Questions: 235 Q&A's Shared By: ronnie
Question 8

A flow has a JMS Publish consume operation followed by a JMS Publish operation. Both of these operations have the default configurations. Which operation is asynchronous and which one is synchronous?

Options:

A.

Publish consume: Synchronous. Publish: Asynchronous.

B.

Publish consume: Asynchronous. Publish: Synchronous

C.

Publish consume: Asynchronous. Publish: Asynchronous

D.

Publish consume: Synchronous. Publish: Synchronous

Discussion
Question 9

Refer to the exhibits.

Questions 9

Questions 9

Set paylaod transformer is set the firstName and lastName of the customer as shown in below images.

What is the correct Dataweave expression which can be added in message attribute of a Logger activity to access firstName (which in this case is Madhav) from the incoming event?

Options:

A.

firstName

B.

customer.firstName

C.

vars."customer.firstName"

D.

vars."customer"."firstName"

Discussion
Question 10

Refer to the exhibits.

Questions 10

The two Mule configuration files belong to the same Mule project. Each HTTP Listener is configured with the same host string and the port number, path, and operation values are shown in the display names.

What is the minimum number of global elements that must be defined to support all these HTTP Listeners?

Options:

A.

1

B.

2

C.

3

D.

4

Discussion
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Question 11

Refer to the exhibits.

Questions 11

What DataWeave expression transforms the conductorIds array to the XML output?

Options:

A.

1. 1. trains:

2. 2. conductorIds map ((engId, index) ->

3. 3. train: {

4. 4. engineerId: engId

5. 5. }

6. 6. )

B.

1. 1. { trains:

2. 2.

3. 3. conductorIds map ((engId, index) ->

4. 4. train: {

5. 5. engineerId: engId

6. 6. }

7. 7. )

8. 8. }

C.

1. 1. trains:

2. 2. {(

3. 3. conductorIds map ((engId, index) ->

4. 4. train: {

5. 5. engineerId: engId

6. 6. }

7. 7. )

8. 8. )}

D.

1. 1. {( trains:

2. 2.

3. 3. conductorIds map ((engId, index) ->

4. 4. train: {

5. 5. engineerId: engId

6. 6. }

7. 7. )

8. 8. )}

Discussion
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