ISTQB Updated ISTQB-CTFL Exam Questions and Answers by effy

To achieve 100% statement coverage, we need to design test cases that ensure every statement in the given pseudo-code is executed at least once. Analyzing the pseudo-code, we notice that there are conditions based on two variables: Gender and Age. To cover all statements, we need to consider the paths that lead to each assignment of the Shoe Size variable.

Gender = Boy, Age <= 3 (Shoe Size assignment is not reached, but the condition is evaluated)

Gender = Boy, Age > 3 AND Age < 5 (Shoe Size = 1)

Gender = Boy, Age >= 5 AND Age < 7 (Shoe Size = 2)

Gender != Boy, Age <= 3 (Again, Shoe Size assignment is not reached, but the condition is evaluated)

Gender != Boy, Age > 3 AND Age < 5 (Shoe Size = 0)

Gender != Boy, Age >= 5 AND Age < 7 (Shoe Size = 1)

However, upon closer inspection, we see that tests 1 and 4 do not contribute to statement coverage as they do not lead to a Shoe Size assignment. Therefore, we only need 4 test cases to achieve 100% statement coverage, making option B the correct answer.

The purpose of a review is to find defects and improve the quality of the work product, not to criticize or blame the author. Reporting defects objectively means describing them factually and constructively, without using negative or emotional language that could offend the author or damage their motivation. This way, the author can take the feedback positively as an effort at improving the product and not as a personal assault. Verified References: A Study Guide to the ISTQB® Foundation Level 2018 Syllabus - Springer, page 138.

The question is about selecting the correct test values for x based on equivalence partitioning. Equivalence partitioning is a software test design technique that divides the input data of a software unit into partitions of equivalent data from which test cases can be derived. In this case, the given equivalence classes are:

(x \leq -100)

(-100 < x < 100)

(100 \leq x < 1000)

(x \geq 1000)

Option D provides a value from each of these partitions:

For (x \leq -100), it gives -1000.

For (-100 < x < 100), it gives -100 and 100.

For (100 \leq x < 1000), it gives 500.

For (x \geq 1000), it gives 1500.

So, option D covers all four given equivalence classes with appropriate values.