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Oracle Updated 1z0-071 Exam Questions and Answers by heather

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Oracle 1z0-071 Exam Overview :

Exam Name: Oracle Database 12c SQL
Exam Code: 1z0-071 Dumps
Vendor: Oracle Certification: Oracle PL
Questions: 326 Q&A's Shared By: heather
Question 88

Which two statements are true about * _TABLES views?

Options:

A.

You must have ANY TABLE system privileges, or be granted object privilges on the table, to viewa tabl e in DBA TABLES.

B.

USER TABLES displays all tables owned by the current user.

C.

You must have ANY TABLE system privileges, or be granted object privileges on the table, to view a table in USER_TABLES.

D.

ALL TABLES displays all tables owned by the current user.

E.

You must have ANY TABLE system privileges, or be granted object privileges on the table, to view a table in ALL_TABLES.

F.

All users can query DBA_TABLES successfully.

Discussion
Question 89

Which two are true about creating tables in an Oracle database?

Options:

A.

A create table statement can specify the maximum number of rows the table will contain.

B.

The same table name can be used for tables in different schemas.

C.

A system privilege is required.

D.

Creating an external table will automatically create a file using the specified directory and file name.

E.

A primary key constraint is manadatory.

Discussion
Question 90

Which statement falls to execute successfully?

Options:

A.

SELECT *

FROM employees e

JOIN department d

WHERE e.department_id=d.department_id

AND d.department_id=90;

B.

SELECT *

FROM employees e

JOIN departments d

ON e.department_id=d.department_id

WHERE d.department_id=90;

C.

SELECT *

FROM employees e

JOIN departments d

ON e.department_id=d.department_id

AND d.department_id=90;

D.

SELECT *

FROM employees e

JOIN departments d

ON d.departments_id=90

WHERE e.department_id=d.department_id;

Discussion
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Question 91

Examine the data in the COLORS table:

Questions 91

Examine the data in the BRICKS table:

Questions 91

Which two queries return all the rows from COLORS?

Options:

A.

SELECT.

FROM bricks b

RIGHT JOIN colors c

ON b. color _rgb_ hex_ value = c. rgb hex_ value;

B.

SELECT

EROM colors C

LEFT JOIN bricks 上

USING (rgb _ hex_ value) ;

C.

SELECT

FROM bricks b

FULL JOIN colors C

ON b. color rgb _ hex_ value = c. rgb _hex_ value;

D.

SELECT *

EROM bricks | b

JOIN colors C

ON b. color_ rgb_ hex_ value =c. rgb _hex value;

E.

SELECT

EROM colors C

LEET JOIN bricks b

ON b. color_ rgb_ hex value = c. rgb. hex.

value

WHERE b. brick_ id > 0;

Discussion
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