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Oracle Updated 1z0-809 Exam Questions and Answers by cece

Page: 7 / 15

Oracle 1z0-809 Exam Overview :

Exam Name: Java SE 8 Programmer II
Exam Code: 1z0-809 Dumps
Vendor: Oracle Certification: Java SE
Questions: 208 Q&A's Shared By: cece
Question 28

Given:

Questions 28

Which is refactored code with functional interfaces?

Options:

A.

Option A 28

B.

Option B 28

C.

Option C 28

D.

Option D 28

Discussion
Question 29

Given the code fragments:

4. void doStuff() throws ArithmeticException, NumberFormatException, Exception {

5. if (Math.random() >-1 throw new Exception (“Try again”);

6. }

and

24. try {

25. doStuff ( ):

26. } catch (ArithmeticException | NumberFormatException | Exception e) {

27. System.out.println (e.getMessage()); }

28. catch (Exception e) {

29. System.out.println (e.getMessage()); }

30. }

Which modification enables the code to print Try again?

Options:

A.

Comment the lines 28, 29 and 30.

B.

Replace line 26 with:} catch (Exception | ArithmeticException | NumberFormatException e) {

C.

Replace line 26 with:} catch (ArithmeticException | NumberFormatException e) {

D.

Replace line 27 with:throw e;

Discussion
Question 30

Given the code fragment:

Questions 30

Which statement can be inserted into line n1 to print 1,2; 1,10; 2,20;?

Options:

A.

BiConsumer c = (i, j) -> {System.out.print (i + “,” + j+ “; “);};

B.

BiFunction c = (i, j) –> {System.out.print (i + “,” + j+ “; “)};

C.

BiConsumer c = (i, j) –> {System.out.print (i + “,” + j+ “; “)};

D.

BiConsumer c = (i, j) –> {System.out.print (i + “,” + j+ “; “);};

Discussion
Question 31

Given the code fragment:

public static void main (String[] args) throws IOException {

BufferedReader brCopy = null;

try (BufferedReader br = new BufferedReader (new FileReader(“employee.txt”))) { //

line n1

br.lines().forEach(c -> System.out.println(c));

brCopy = br;//line n2

}

brCopy.ready(); //line n3;

}

Assume that the ready method of the BufferedReader, when called on a closed BufferedReader, throws an exception, and employee.txt is accessible and contains valid text.

What is the result?

Options:

A.

A compilation error occurs at line n3.

B.

A compilation error occurs at line n1.

C.

A compilation error occurs at line n2.

D.

The code prints the content of the employee.txt file and throws an exception at line n3.

Discussion
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